From 72af0dedf9e18911da65b9a5c4906689e868d9fc Mon Sep 17 00:00:00 2001
From: Richard-Qin-X <richard.qin.001@gmail.com>
Date: Mon, 8 Jun 2026 17:10:31 +0800
Subject: [legacy] Add functional and performance test suites

---
 rcc-legacy/tests/upload/test1_2.sy | 105 +++++++++++++++++++++++++++++++++++++
 1 file changed, 105 insertions(+)
 create mode 100644 rcc-legacy/tests/upload/test1_2.sy

(limited to 'rcc-legacy/tests/upload/test1_2.sy')

diff --git a/rcc-legacy/tests/upload/test1_2.sy b/rcc-legacy/tests/upload/test1_2.sy
new file mode 100644
index 0000000..3dc1d51
--- /dev/null
+++ b/rcc-legacy/tests/upload/test1_2.sy
@@ -0,0 +1,105 @@
+int a[1000];
+int b[1000];
+int c[1000];
+int lena;
+int lenb;
+int lenc;
+
+
+void add() {  //b=b+a
+	int i;
+	
+	if (lena>lenb) {
+		lenc = lena;
+	}
+	else{
+		lenc = lenb;
+	}
+	i=0;
+	while (i<=lenc) {
+		c[i] = 0;
+		i=i+1;
+	}
+	i=0;
+	while (i<lenc) {
+		c[i] = c[i] + (a[i] + b[i]);
+		if (c[i] >= 10) {
+			c[i+1] = c[i+1] + 1;
+			c[i] = c[i] - 10;
+		}
+		i=i+1;
+	}
+	if (c[lenc]) {   //有进位 数组c的长度+1 
+		lenc = lenc+1;
+	}
+	//b<-c
+	i=0;
+	while (i<lenc) {
+		b[i] = c[i];
+		i=i+1;
+	}
+	lenb = lenc;
+}
+
+ 
+void mult(int n) {  //a=a*n  n最大50,位数=lena+2 
+	int i;
+	
+	i=0;
+	while (i<=lena+2) {
+		c[i] = 0;
+		i=i+1;
+	}	
+	lenc = lena;
+	i=0;
+	while (i<lenc) {
+		c[i] = c[i] + a[i] * n;
+		if (c[i] >= 10) {
+			c[i+1] = c[i+1] + (c[i] / 10);
+			c[i] = c[i] % 10;
+		}
+		i=i+1;
+	}
+	//最高位的值可能>=10 要展开成多位 
+	while (c[lenc] >= 10) {
+		c[lenc+1] = c[lenc+1] + (c[lenc] / 10);
+		c[lenc] = c[lenc] % 10;
+		lenc = lenc+1;
+	}
+	if (c[lenc]) {  //0<最高位<=10 也要长度+1 
+		lenc = lenc+1;
+	}
+	//a<-c 
+	i=0;
+	while (i<lenc) {
+		a[i] = c[i];
+		i=i+1;
+	}
+	lena = lenc;
+}
+
+int main()
+{
+	int n;
+	int i;
+
+	n = getint();
+	a[0] = 1;  //a=1
+	lena = 1;
+	b[0] = 0;  //b=0
+	lenb = 1;
+	
+	i=1;
+	while (i<=n) {
+		mult(i);  //a=a*i
+		add();    //b=b+a
+		i=i+1; 
+	}
+	i=lenb-1;
+	while (i>=0) {
+		putint(b[i]);
+		i=i-1;
+	} 
+	putch(10);
+	return 0; 
+}
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